Dos下获取系统时间的代码

2012年11月30日

  
rem DOS get current time  
rem =======================  
rem get yyyy/mm/dd  
set mydate=%DATE:~0,10%  
echo %mydate%  
rem =======================  
rem get yyyy  
set yyyy=%DATE:~0,4%  
echo %yyyy%  
rem =======================  
rem get mm  
set mm=%DATE:~5,2%  
echo %mm%  
rem =======================  
rem get dd  
set dd=%DATE:~8,2%  
echo %dd%  
rem =======================  
rem get yyyy-mm-dd  
set curdate=%yyyy%-%mm%-%dd%  
echo %curdate%

其实bat中获取时间就是利用截取日期字符串的方法

DOS下有字符处理的方法的，总结如下：

在这个日期格式下：”2013-07-22 星期一”，这个%DATE:~0,10%得到的是2013-07-22
说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。

输出：

C:Documents and SettingsAdministrator>rem DOS get current time
C:Documents and SettingsAdministrator>rem =======================
C:Documents and SettingsAdministrator>rem get yyyy/mm/dd
C:Documents and SettingsAdministrator>set mydate=2013-07-22
C:Documents and SettingsAdministrator>echo 2013-07-22
2013-07-22
C:Documents and SettingsAdministrator>rem =======================
C:Documents and SettingsAdministrator>rem get yyyy
C:Documents and SettingsAdministrator>set yyyy=2013
C:Documents and SettingsAdministrator>echo 2013
2013
C:Documents and SettingsAdministrator>rem =======================
C:Documents and SettingsAdministrator>rem get mm
C:Documents and SettingsAdministrator>set mm=07
C:Documents and SettingsAdministrator>echo 07
07
C:Documents and SettingsAdministrator>rem =======================
C:Documents and SettingsAdministrator>rem get dd
C:Documents and SettingsAdministrator>set dd=22
C:Documents and SettingsAdministrator>echo 22
22
C:Documents and SettingsAdministrator>rem =======================
C:Documents and SettingsAdministrator>rem get yyyy-mm-dd
C:Documents and SettingsAdministrator>set curdate=2013 -07 -22
C:Documents and SettingsAdministrator>echo 2013 -07 -22
2013 -07 -22
C:Documents and SettingsAdministrator>