ios – 基于一组超级有序字符串对NSStrings的NSArray进行排序

NSArray *objects = @[@"Stin",@"Foo",@"Ray",@"Space"];

现在我需要根据字符串的顺序对此数组进行排序.

NSArray *sortOrder = @[@"John",@"Space",@"Star",@"Stin"];

所以答案应该是

NSArray *sorted = @[@"Foo",@"Stin"];

我怎样才能做到这一点？

回答：
根据dasblinkenlight的接受的答案,我做了以下,它有魅力.

NSMutableArray *objects = @[@"Star",@"Stin",@"John"];
NSArray *sortOrder = @[@"John",@"Stin"];

[objects sortUsingComparator:^NSComparisonResult(id obj1,id obj2) {
    int index1 = [sortOrder indexOfObject:obj1];
    int index2 = [sortOrder indexOfObject:obj2];

    if (index1 > index2)
        return NSOrderedDescending;
    if (index1 < index2)
        return NSOrderedAscending;
    return NSOrderedSame;
}];