ios – RxSwift重载tableview

2019年12月18日作者：佚名

let officialAccountObservable : Observable<[SearchUser]> = SearchAPI.sharedAPI.suggestAccounts()

        officialAccountObservable.bind(to: tableView.rx.items(cellIdentifier: "followcell",cellType: FollowCell.self)) {
            (index,user,cell) in
            if user.profileImagePath.isEmpty == false {
                cell.profile.af_setImage(withURL: URL.init(string: user.profileImagePath)!)
            }else {
                cell.profile.image = UIImage.init(named: "icon_user_03")
            }
            cell.nickName.text = user.nickName

            cell.follow.rx.tap
                .debounce(0.3,scheduler: MainScheduler.instance)
                .subscribe(onNext: {
                    [unowned self] in
                    cell.setFollow(user: user,completion: { (result) in
                        if(result == true){

                        }
                    })
                }).addDisposableTo(self.disposeBag)
        }.addDisposableTo(disposeBag)

func suggestAccounts() -> Observable<[SearchUser]> {

    let uri = Constants.VyrlSearchURL.suggestUsers

    return Observable.create { observer in
        let request = Alamofire.request(uri,method: .get,parameters: nil,encoding: JSONEncoding.default,headers: Constants.VyrlAPIConstants.getHeader()).responseArray { (response: DataResponse<[SearchUser]>) in
            let value = response.result.value

            observer.onNext(value!)
            observer.onCompleted()
        }

        return Disposables.create(with: request.cancel)
    }
}

我想在代码中重新加载表视图(result == true)
对于重新加载,必须收到OfficialAccountObservable.
我的代码已经全部结束,我想知道如何在该状态下更新它.

解决方法

AFAIK,这是这样做的标准方式 –

let source = PublishSubject<Observable<[SearchUser]>>()
let officialAccountObservable: Observable<[SearchUser]> = source.switchLatest()
source.onNext(suggestAccounts()) // every call will refresh your table

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