ios – 以编程方式禁用UIButton单击时的突出显示

必须有办法做到这一点,但我找不到它.我有一个以编程方式创建的按钮：

UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
button.frame = CGRectMake(25,self.view.frame.size.height/4,200,350);
[button setTitle:@"Inbox" forState:UIControlStateNormal];
[button addTarget:self action:@selector(popViewController:) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:button];

我想要的只是按钮在触摸时不以任何方式突出显示或改变外观.到目前为止,我在创建按钮时尝试了以下操作：

[button setBackgroundImage:[UIImage imageNamed:nil] forState:UIControlStateSelected | UIControlStateHighlighted];

和

[button setBackgroundImage:nil forState:UIControlStateSelected];

和

[button setAdjustsImageWhenHighlighted:NO];

和

button.showsTouchWhenHighlighted = NO;

然后在我尝试的按钮操作中：

[sender setHighlighted:!sender.isHighlighted];

和

[sender setSelected:!sender.isSelected];

这些都不起作用.

UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom];